Simulasi Matematika IPS 2019
8. 0∫1(3x - 1)(x + 2) dx = ...
a. -1/2
b. 1/2
c. 3/2
d. 4
e. 6
Jawaban : C
0∫1(3x - 1)(x + 2)
= 0∫1(3x2 + 6x - x - 2)
= 0∫1(3x2 + 5x - 2)
= [x3 + 5/2 x2 - 2x + c]01
= (13 + 5/2 12 - 2 . 1 + c) - (03 + 5/2 02 - 2 . 0 + c)
= 1 + 5/2 - 2
= 7/2 - 2
= 3/2
8. 0∫1(3x - 1)(x + 2) dx = ...
a. -1/2
b. 1/2
c. 3/2
d. 4
e. 6
Jawaban : C
0∫1(3x - 1)(x + 2)
= 0∫1(3x2 + 6x - x - 2)
= 0∫1(3x2 + 5x - 2)
= [x3 + 5/2 x2 - 2x + c]01
= (13 + 5/2 12 - 2 . 1 + c) - (03 + 5/2 02 - 2 . 0 + c)
= 1 + 5/2 - 2
= 7/2 - 2
= 3/2
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