Simulasi Matematika IPS 2019
6. Nilai sin 150° + sin 270° tan 315° ialah ...
a. -1/2
b. -1
c. 1/2
d. 1/2 √3
e. 1 1/2
Jawaban :
sin 150° = sin (90 + 60)°
sin 150° = cos (60)°
sin 150° = 1/2
sin 270° = sin (180 + 90)°
sin 270° = - sin (90)°
sin 270° = -1
menghitung tan 315°
tan 315° = sin 315° / cos 315°
sin 315° = sin (270 + 45)°
sin 315° = - cos (45)°
sin 315° = - 1/2 √2
cos 315° = cos (270 + 45)°
cos 315° = sin (45)°
cos 315° = 1/2 √2
tan 315° = sin 315° / cos 315°
tan 315° = - 1/2 √2 / 1/2 √2
tan 315° = - 1
sin 150° + sin 270° tan 315°
= 1/2 + -1 . -1
= 1/2 + 1
= 1 1/2
6. Nilai sin 150° + sin 270° tan 315° ialah ...
a. -1/2
b. -1
c. 1/2
d. 1/2 √3
e. 1 1/2
Jawaban :
sin 150° = sin (90 + 60)°
sin 150° = cos (60)°
sin 150° = 1/2
sin 270° = sin (180 + 90)°
sin 270° = - sin (90)°
sin 270° = -1
menghitung tan 315°
tan 315° = sin 315° / cos 315°
sin 315° = sin (270 + 45)°
sin 315° = - cos (45)°
sin 315° = - 1/2 √2
cos 315° = cos (270 + 45)°
cos 315° = sin (45)°
cos 315° = 1/2 √2
tan 315° = sin 315° / cos 315°
tan 315° = - 1/2 √2 / 1/2 √2
tan 315° = - 1
sin 150° + sin 270° tan 315°
= 1/2 + -1 . -1
= 1/2 + 1
= 1 1/2
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